直接先统计每种宗教的信仰人数再统一累加即可。

#include <bits/stdc++.h>
using namespace std;
int a[1000012], b[1000012];
int main()
{
	ios::sync_with_stdio(0);
	int n, m, k;
	cin >> n >> m >> k;
	for (int i = 1; i <= n; i++)
	{
		int x;
		cin >> x;
		a[x]++;
	}
	for (int i = 1; i <= m; i++)
	{
		int s;
		cin >> s;
		while (s--)
		{
			int x;
			cin >> x;
			b[x] += a[i];
		}
	}
	for (int i = 1; i <= k - 1; i++)
		cout << b[i] << ' ';
	cout << b[k] << endl;
	return 0;
}